-7+3+7p+2=11(1-11p)+8(p-2)

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Solution for -7+3+7p+2=11(1-11p)+8(p-2) equation: 



-7+3+7p+2=11(1-11p)+8(p-2)

We move all terms to the left:

-7+3+7p+2-(11(1-11p)+8(p-2))=0

We add all the numbers together, and all the variables

7p-(11(-11p+1)+8(p-2))-7+3+2=0

We add all the numbers together, and all the variables

7p-(11(-11p+1)+8(p-2))-2=0



We calculate terms in parentheses: -(11(-11p+1)+8(p-2)), so:

11(-11p+1)+8(p-2)

We multiply parentheses

-121p+8p+11-16

We add all the numbers together, and all the variables

-113p-5

Back to the equation:

-(-113p-5)



We get rid of parentheses

7p+113p+5-2=0

We add all the numbers together, and all the variables

120p+3=0

We move all terms containing p to the left, all other terms to the right

120p=-3

p=-3/120

p=-1/40

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