-7+2(2-2x)-(1-x)=5x-2(x-3)

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Solution for -7+2(2-2x)-(1-x)=5x-2(x-3) equation: 



-7+2(2-2x)-(1-x)=5x-2(x-3)

We move all terms to the left:

-7+2(2-2x)-(1-x)-(5x-2(x-3))=0

We add all the numbers together, and all the variables

2(-2x+2)-(-1x+1)-(5x-2(x-3))-7=0

We multiply parentheses

-4x-(-1x+1)-(5x-2(x-3))+4-7=0

We get rid of parentheses

-4x+1x-(5x-2(x-3))-1+4-7=0



We calculate terms in parentheses: -(5x-2(x-3)), so:

5x-2(x-3)

We multiply parentheses

5x-2x+6

We add all the numbers together, and all the variables

3x+6

Back to the equation:

-(3x+6)



We add all the numbers together, and all the variables

-3x-(3x+6)-4=0

We get rid of parentheses

-3x-3x-6-4=0

We add all the numbers together, and all the variables

-6x-10=0

We move all terms containing x to the left, all other terms to the right

-6x=10

x=10/-6

x=-1+2/3

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