-7(z-6)3z-8=

Solution for -7(z-6)3z-8= equation:

-7(z-6)3z-8=

We move all terms to the left:

-7(z-6)3z-8-()=0

We add all the numbers together, and all the variables

-7(z-6)3z=0

We multiply parentheses

-21z^2+126z=0

a = -21; b = 126; c = 0;
Δ = b2-4ac
Δ = 1262-4·(-21)·0
Δ = 15876
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$z_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$z_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{15876}=126$
$z_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(126)-126}{2*-21}=\frac{-252}{-42}
=+6
$
$z_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(126)+126}{2*-21}=\frac{0}{-42}
=0
$