-7(z+1)+4(3z-4)=4+10

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Solution for -7(z+1)+4(3z-4)=4+10 equation: 



-7(z+1)+4(3z-4)=4+10

We move all terms to the left:

-7(z+1)+4(3z-4)-(4+10)=0

We add all the numbers together, and all the variables

-7(z+1)+4(3z-4)-14=0

We multiply parentheses

-7z+12z-7-16-14=0

We add all the numbers together, and all the variables

5z-37=0

We move all terms containing z to the left, all other terms to the right

5z=37

z=37/5

z=7+2/5

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