-7(y+1)=2y-6+2(3y+2)

Solution for -7(y+1)=2y-6+2(3y+2) equation:

-7(y+1)=2y-6+2(3y+2)

We move all terms to the left:

-7(y+1)-(2y-6+2(3y+2))=0

We multiply parentheses

-7y-(2y-6+2(3y+2))-7=0


We calculate terms in parentheses: -(2y-6+2(3y+2)), so:

2y-6+2(3y+2)

determiningTheFunctionDomain
2y+2(3y+2)-6

We multiply parentheses

2y+6y+4-6

We add all the numbers together, and all the variables

8y-2

Back to the equation:

-(8y-2)


We get rid of parentheses

-7y-8y+2-7=0

We add all the numbers together, and all the variables

-15y-5=0

We move all terms containing y to the left, all other terms to the right

-15y=5

y=5/-15

y=-1/3