-7(x+1)=x-3+2(2x+6)

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Solution for -7(x+1)=x-3+2(2x+6) equation: 



-7(x+1)=x-3+2(2x+6)

We move all terms to the left:

-7(x+1)-(x-3+2(2x+6))=0

We multiply parentheses

-7x-(x-3+2(2x+6))-7=0



We calculate terms in parentheses: -(x-3+2(2x+6)), so:

x-3+2(2x+6)

determiningTheFunctionDomain
x+2(2x+6)-3

We multiply parentheses

x+4x+12-3

We add all the numbers together, and all the variables

5x+9

Back to the equation:

-(5x+9)



We get rid of parentheses

-7x-5x-9-7=0

We add all the numbers together, and all the variables

-12x-16=0

We move all terms containing x to the left, all other terms to the right

-12x=16

x=16/-12

x=-1+1/3

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