-7(x+1)+4x-(x+2)=3(5-x)+12x

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Solution for -7(x+1)+4x-(x+2)=3(5-x)+12x equation: 



-7(x+1)+4x-(x+2)=3(5-x)+12x

We move all terms to the left:

-7(x+1)+4x-(x+2)-(3(5-x)+12x)=0

We add all the numbers together, and all the variables

-7(x+1)+4x-(x+2)-(3(-1x+5)+12x)=0

We add all the numbers together, and all the variables

4x-7(x+1)-(x+2)-(3(-1x+5)+12x)=0

We multiply parentheses

4x-7x-(x+2)-(3(-1x+5)+12x)-7=0

We get rid of parentheses

4x-7x-x-(3(-1x+5)+12x)-2-7=0



We calculate terms in parentheses: -(3(-1x+5)+12x), so:

3(-1x+5)+12x

We add all the numbers together, and all the variables

12x+3(-1x+5)

We multiply parentheses

12x-3x+15

We add all the numbers together, and all the variables

9x+15

Back to the equation:

-(9x+15)



We add all the numbers together, and all the variables

-4x-(9x+15)-9=0

We get rid of parentheses

-4x-9x-15-9=0

We add all the numbers together, and all the variables

-13x-24=0

We move all terms containing x to the left, all other terms to the right

-13x=24

x=24/-13

x=-1+11/13

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