-7(v+3)3v+6=8v+8

Solution for -7(v+3)3v+6=8v+8 equation:

-7(v+3)3v+6=8v+8

We move all terms to the left:

-7(v+3)3v+6-(8v+8)=0

We multiply parentheses

-21v^2-63v-(8v+8)+6=0

We get rid of parentheses

-21v^2-63v-8v-8+6=0

We add all the numbers together, and all the variables

-21v^2-71v-2=0

a = -21; b = -71; c = -2;
Δ = b2-4ac
Δ = -712-4·(-21)·(-2)
Δ = 4873
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$v_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$v_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$v_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-71)-\sqrt{4873}}{2*-21}=\frac{71-\sqrt{4873}}{-42}
$
$v_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-71)+\sqrt{4873}}{2*-21}=\frac{71+\sqrt{4873}}{-42}
$