-7(n+1)+7(n+3)=3-3n+n-7

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Solution for -7(n+1)+7(n+3)=3-3n+n-7 equation: 



-7(n+1)+7(n+3)=3-3n+n-7

We move all terms to the left:

-7(n+1)+7(n+3)-(3-3n+n-7)=0

We add all the numbers together, and all the variables

-7(n+1)+7(n+3)-(-2n-4)=0

We multiply parentheses

-7n+7n-(-2n-4)-7+21=0

We get rid of parentheses

-7n+7n+2n+4-7+21=0

We add all the numbers together, and all the variables

2n+18=0

We move all terms containing n to the left, all other terms to the right

2n=-18

n=-18/2

n=-9

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