-7(4z-12)=30

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Solution for -7(4z-12)=30 equation: 



-7(4z-12)=30

We move all terms to the left:

-7(4z-12)-(30)=0

We multiply parentheses

-28z+84-30=0

We add all the numbers together, and all the variables

-28z+54=0

We move all terms containing z to the left, all other terms to the right

-28z=-54

z=-54/-28

z=1+13/14

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