-7(3y-1)+8y=5(y+3)

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Solution for -7(3y-1)+8y=5(y+3) equation: 



-7(3y-1)+8y=5(y+3)

We move all terms to the left:

-7(3y-1)+8y-(5(y+3))=0

We add all the numbers together, and all the variables

8y-7(3y-1)-(5(y+3))=0

We multiply parentheses

8y-21y-(5(y+3))+7=0



We calculate terms in parentheses: -(5(y+3)), so:

5(y+3)

We multiply parentheses

5y+15

Back to the equation:

-(5y+15)



We add all the numbers together, and all the variables

-13y-(5y+15)+7=0

We get rid of parentheses

-13y-5y-15+7=0

We add all the numbers together, and all the variables

-18y-8=0

We move all terms containing y to the left, all other terms to the right

-18y=8

y=8/-18

y=-4/9

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