-7(2y-3)+7y=7(y+2)

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Solution for -7(2y-3)+7y=7(y+2) equation: 



-7(2y-3)+7y=7(y+2)

We move all terms to the left:

-7(2y-3)+7y-(7(y+2))=0

We add all the numbers together, and all the variables

7y-7(2y-3)-(7(y+2))=0

We multiply parentheses

7y-14y-(7(y+2))+21=0



We calculate terms in parentheses: -(7(y+2)), so:

7(y+2)

We multiply parentheses

7y+14

Back to the equation:

-(7y+14)



We add all the numbers together, and all the variables

-7y-(7y+14)+21=0

We get rid of parentheses

-7y-7y-14+21=0

We add all the numbers together, and all the variables

-14y+7=0

We move all terms containing y to the left, all other terms to the right

-14y=-7

y=-7/-14

y=1/2

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