-7(1x+4)=3x+12

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Solution for -7(1x+4)=3x+12 equation: 



-7(1x+4)=3x+12

We move all terms to the left:

-7(1x+4)-(3x+12)=0

We add all the numbers together, and all the variables

-7(x+4)-(3x+12)=0

We multiply parentheses

-7x-(3x+12)-28=0

We get rid of parentheses

-7x-3x-12-28=0

We add all the numbers together, and all the variables

-10x-40=0

We move all terms containing x to the left, all other terms to the right

-10x=40

x=40/-10

x=-4

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