-7(1-3x)+8=8x+40

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Solution for -7(1-3x)+8=8x+40 equation: 



-7(1-3x)+8=8x+40

We move all terms to the left:

-7(1-3x)+8-(8x+40)=0

We add all the numbers together, and all the variables

-7(-3x+1)-(8x+40)+8=0

We multiply parentheses

21x-(8x+40)-7+8=0

We get rid of parentheses

21x-8x-40-7+8=0

We add all the numbers together, and all the variables

13x-39=0

We move all terms containing x to the left, all other terms to the right

13x=39

x=39/13

x=3

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