-7(-4y+3)-3y=7(y-4)-9

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Solution for -7(-4y+3)-3y=7(y-4)-9 equation: 



-7(-4y+3)-3y=7(y-4)-9

We move all terms to the left:

-7(-4y+3)-3y-(7(y-4)-9)=0

We add all the numbers together, and all the variables

-3y-7(-4y+3)-(7(y-4)-9)=0

We multiply parentheses

-3y+28y-(7(y-4)-9)-21=0



We calculate terms in parentheses: -(7(y-4)-9), so:

7(y-4)-9

We multiply parentheses

7y-28-9

We add all the numbers together, and all the variables

7y-37

Back to the equation:

-(7y-37)



We add all the numbers together, and all the variables

25y-(7y-37)-21=0

We get rid of parentheses

25y-7y+37-21=0

We add all the numbers together, and all the variables

18y+16=0

We move all terms containing y to the left, all other terms to the right

18y=-16

y=-16/18

y=-8/9

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