-7(-3y+3)-9y=3(y-2)-9

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Solution for -7(-3y+3)-9y=3(y-2)-9 equation: 



-7(-3y+3)-9y=3(y-2)-9

We move all terms to the left:

-7(-3y+3)-9y-(3(y-2)-9)=0

We add all the numbers together, and all the variables

-9y-7(-3y+3)-(3(y-2)-9)=0

We multiply parentheses

-9y+21y-(3(y-2)-9)-21=0



We calculate terms in parentheses: -(3(y-2)-9), so:

3(y-2)-9

We multiply parentheses

3y-6-9

We add all the numbers together, and all the variables

3y-15

Back to the equation:

-(3y-15)



We add all the numbers together, and all the variables

12y-(3y-15)-21=0

We get rid of parentheses

12y-3y+15-21=0

We add all the numbers together, and all the variables

9y-6=0

We move all terms containing y to the left, all other terms to the right

9y=6

y=6/9

y=2/3

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