-7(-2y+3)-4y=6(y-5)-9

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Solution for -7(-2y+3)-4y=6(y-5)-9 equation: 



-7(-2y+3)-4y=6(y-5)-9

We move all terms to the left:

-7(-2y+3)-4y-(6(y-5)-9)=0

We add all the numbers together, and all the variables

-4y-7(-2y+3)-(6(y-5)-9)=0

We multiply parentheses

-4y+14y-(6(y-5)-9)-21=0



We calculate terms in parentheses: -(6(y-5)-9), so:

6(y-5)-9

We multiply parentheses

6y-30-9

We add all the numbers together, and all the variables

6y-39

Back to the equation:

-(6y-39)



We add all the numbers together, and all the variables

10y-(6y-39)-21=0

We get rid of parentheses

10y-6y+39-21=0

We add all the numbers together, and all the variables

4y+18=0

We move all terms containing y to the left, all other terms to the right

4y=-18

y=-18/4

y=-4+1/2

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