-6y+17=3y(y-31/3)

Solution for -6y+17=3y(y-31/3) equation:

-6y+17=3y(y-31/3)

We move all terms to the left:

-6y+17-(3y(y-31/3))=0

We add all the numbers together, and all the variables

-6y-(3y(+y-31/3))+17=0

We multiply all the terms by the denominator


-6y*3))-(3y(+y-31+17*3))=0

We add all the numbers together, and all the variables

-6y*3))-(3y(y+20))=0

We add all the numbers together, and all the variables

-6y*3))-(3y(y=0

Wy multiply elements

-18y^2=0

a = -18; b = 0; c = 0;
Δ = b2-4ac
Δ = 02-4·(-18)·0
Δ = 0
Delta is equal to zero, so there is only one solution to the equation

                              Stosujemy wzór:
$y=\frac{-b}{2a}=\frac{0}{-36}=0$