-6x-4+3(3x-2)=4(x+2)-1

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Solution for -6x-4+3(3x-2)=4(x+2)-1 equation: 



-6x-4+3(3x-2)=4(x+2)-1

We move all terms to the left:

-6x-4+3(3x-2)-(4(x+2)-1)=0

We multiply parentheses

-6x+9x-(4(x+2)-1)-6-4=0



We calculate terms in parentheses: -(4(x+2)-1), so:

4(x+2)-1

We multiply parentheses

4x+8-1

We add all the numbers together, and all the variables

4x+7

Back to the equation:

-(4x+7)



We add all the numbers together, and all the variables

3x-(4x+7)-10=0

We get rid of parentheses

3x-4x-7-10=0

We add all the numbers together, and all the variables

-1x-17=0

We move all terms containing x to the left, all other terms to the right

-x=17

x=17/-1

x=-17

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