-6x-4(3x-4)=(x-12)

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Solution for -6x-4(3x-4)=(x-12) equation:



-6x-4(3x-4)=(x-12)
We move all terms to the left:
-6x-4(3x-4)-((x-12))=0
We multiply parentheses
-6x-12x-((x-12))+16=0
We calculate terms in parentheses: -((x-12)), so:
(x-12)
We get rid of parentheses
x-12
Back to the equation:
-(x-12)
We add all the numbers together, and all the variables
-18x-(x-12)+16=0
We get rid of parentheses
-18x-x+12+16=0
We add all the numbers together, and all the variables
-19x+28=0
We move all terms containing x to the left, all other terms to the right
-19x=-28
x=-28/-19
x=1+9/19

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