-6x+4-4x=2x(3x+6)

Solution for -6x+4-4x=2x(3x+6) equation:

-6x+4-4x=2x(3x+6)

We move all terms to the left:

-6x+4-4x-(2x(3x+6))=0

We add all the numbers together, and all the variables

-10x-(2x(3x+6))+4=0


We calculate terms in parentheses: -(2x(3x+6)), so:

2x(3x+6)

We multiply parentheses

6x^2+12x

Back to the equation:

-(6x^2+12x)


We get rid of parentheses

-6x^2-10x-12x+4=0

We add all the numbers together, and all the variables

-6x^2-22x+4=0

a = -6; b = -22; c = +4;
Δ = b2-4ac
Δ = -222-4·(-6)·4
Δ = 580
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{580}=\sqrt{4*145}=\sqrt{4}*\sqrt{145}=2\sqrt{145}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-22)-2\sqrt{145}}{2*-6}=\frac{22-2\sqrt{145}}{-12}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-22)+2\sqrt{145}}{2*-6}=\frac{22+2\sqrt{145}}{-12}
$