-6x(x-4)=-25+x

Solution for -6x(x-4)=-25+x equation:

-6x(x-4)=-25+x

We move all terms to the left:

-6x(x-4)-(-25+x)=0

We add all the numbers together, and all the variables

-6x(x-4)-(x-25)=0

We multiply parentheses

-6x^2+24x-(x-25)=0

We get rid of parentheses

-6x^2+24x-x+25=0

We add all the numbers together, and all the variables

-6x^2+23x+25=0

a = -6; b = 23; c = +25;
Δ = b2-4ac
Δ = 232-4·(-6)·25
Δ = 1129
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(23)-\sqrt{1129}}{2*-6}=\frac{-23-\sqrt{1129}}{-12}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(23)+\sqrt{1129}}{2*-6}=\frac{-23+\sqrt{1129}}{-12}
$