-6x(10+2x)=-192

Solution for -6x(10+2x)=-192 equation:

-6x(10+2x)=-192

We move all terms to the left:

-6x(10+2x)-(-192)=0

We add all the numbers together, and all the variables

-6x(2x+10)-(-192)=0

We add all the numbers together, and all the variables

-6x(2x+10)+192=0

We multiply parentheses

-12x^2-60x+192=0

a = -12; b = -60; c = +192;
Δ = b2-4ac
Δ = -602-4·(-12)·192
Δ = 12816
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{12816}=\sqrt{144*89}=\sqrt{144}*\sqrt{89}=12\sqrt{89}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-60)-12\sqrt{89}}{2*-12}=\frac{60-12\sqrt{89}}{-24}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-60)+12\sqrt{89}}{2*-12}=\frac{60+12\sqrt{89}}{-24}
$