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-6x(-8-4x)=96
We move all terms to the left:
-6x(-8-4x)-(96)=0
We add all the numbers together, and all the variables
-6x(-4x-8)-96=0
We multiply parentheses
24x^2+48x-96=0
a = 24; b = 48; c = -96;
Δ = b2-4ac
Δ = 482-4·24·(-96)
Δ = 11520
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{11520}=\sqrt{2304*5}=\sqrt{2304}*\sqrt{5}=48\sqrt{5}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(48)-48\sqrt{5}}{2*24}=\frac{-48-48\sqrt{5}}{48} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(48)+48\sqrt{5}}{2*24}=\frac{-48+48\sqrt{5}}{48} $
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