-6m+48m2=0

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Solution for -6m+48m2=0 equation: 



-6m+48m^2=0

a = 48; b = -6; c = 0;
Δ = b2-4ac
Δ = -62-4·48·0
Δ = 36
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$m_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$m_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{36}=6$


$m_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-6)-6}{2*48}=\frac{0}{96}
=0
$


$m_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-6)+6}{2*48}=\frac{12}{96}
=1/8
$

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