-6a-32=a-5(-4+4a)

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Solution for -6a-32=a-5(-4+4a) equation: 



-6a-32=a-5(-4+4a)

We move all terms to the left:

-6a-32-(a-5(-4+4a))=0

We add all the numbers together, and all the variables

-6a-(a-5(4a-4))-32=0



We calculate terms in parentheses: -(a-5(4a-4)), so:

a-5(4a-4)

We multiply parentheses

a-20a+20

We add all the numbers together, and all the variables

-19a+20

Back to the equation:

-(-19a+20)



We get rid of parentheses

-6a+19a-20-32=0

We add all the numbers together, and all the variables

13a-52=0

We move all terms containing a to the left, all other terms to the right

13a=52

a=52/13

a=4

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