-6=2/5(x-16)

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Solution for -6=2/5(x-16) equation:



-6=2/5(x-16)
We move all terms to the left:
-6-(2/5(x-16))=0
Domain of the equation: 5(x-16))!=0
x∈R
We multiply all the terms by the denominator
-(2-6*5(x-16))=0
We calculate terms in parentheses: -(2-6*5(x-16)), so:
2-6*5(x-16)
determiningTheFunctionDomain -6*5(x-16)+2
Wy multiply elements
-30x(x+2
Back to the equation:
-(-30x(x+2)
We calculate terms in parentheses: -(-30x(x+2), so:
-30x(x+2
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-30x(x+2
We calculate terms in parentheses: -(-30x(x+2), so:
-30x(x+2
We calculate terms in parentheses: -(-30x(x+2), so:
-30x(x+2
We calculate terms in parentheses: -(-30x(x+2), so:
-30x(x+2
We calculate terms in parentheses: -(-30x(x+2), so:
-30x(x+2
We calculate terms in parentheses: -(-30x(x+2), so:
-30x(x+2
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-30x(x+2
We calculate terms in parentheses: -(-30x(x+2), so:
-30x(x+2
We calculate terms in parentheses: -(-30x(x+2), so:
-30x(x+2
We calculate terms in parentheses: -(-30x(x+2), so:
-30x(x+2
We calculate terms in parentheses: -(-30x(x+2), so:
-30x(x+2
We calculate terms in parentheses: -(-30x(x+2), so:
-30x(x+2
We calculate terms in parentheses: -(-30x(x+2), so:
-30x(x+2
We calculate terms in parentheses: -(-30x(x+2), so:
-30x(x+2
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-30x(x+2
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-30x(x+2
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-30x(x+2
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-30x(x+2
We calculate terms in parentheses: -(-30x(x+2), so:
-30x(x+2
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-30x(x+2
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