-68=-2p(p+3)

Solution for -68=-2p(p+3) equation:

-68=-2p(p+3)

We move all terms to the left:

-68-(-2p(p+3))=0


We calculate terms in parentheses: -(-2p(p+3)), so:

-2p(p+3)

We multiply parentheses

-2p^2-6p

Back to the equation:

-(-2p^2-6p)


We get rid of parentheses

2p^2+6p-68=0

a = 2; b = 6; c = -68;
Δ = b2-4ac
Δ = 62-4·2·(-68)
Δ = 580
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$p_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$p_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{580}=\sqrt{4*145}=\sqrt{4}*\sqrt{145}=2\sqrt{145}$
$p_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(6)-2\sqrt{145}}{2*2}=\frac{-6-2\sqrt{145}}{4}
$
$p_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(6)+2\sqrt{145}}{2*2}=\frac{-6+2\sqrt{145}}{4}
$