-64-(2x+2)=4(x+3)+7x

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Solution for -64-(2x+2)=4(x+3)+7x equation: 



-64-(2x+2)=4(x+3)+7x

We move all terms to the left:

-64-(2x+2)-(4(x+3)+7x)=0

We get rid of parentheses

-2x-(4(x+3)+7x)-2-64=0



We calculate terms in parentheses: -(4(x+3)+7x), so:

4(x+3)+7x

We add all the numbers together, and all the variables

7x+4(x+3)

We multiply parentheses

7x+4x+12

We add all the numbers together, and all the variables

11x+12

Back to the equation:

-(11x+12)



We add all the numbers together, and all the variables

-2x-(11x+12)-66=0

We get rid of parentheses

-2x-11x-12-66=0

We add all the numbers together, and all the variables

-13x-78=0

We move all terms containing x to the left, all other terms to the right

-13x=78

x=78/-13

x=-6

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