-6/7(1-7x)=2/3x

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Solution for -6/7(1-7x)=2/3x equation: 



-6/7(1-7x)=2/3x

We move all terms to the left:

-6/7(1-7x)-(2/3x)=0



Domain of the equation: 7(1-7x)!=0

x∈R





Domain of the equation: 3x)!=0

x!=0/1

x!=0

x∈R



We add all the numbers together, and all the variables

-6/7(-7x+1)-(+2/3x)=0

We get rid of parentheses

-6/7(-7x+1)-2/3x=0

We calculate fractions


(-18x)/(-147x^2+21x)+(-14x(-)/(-147x^2+21x)=0



We calculate terms in parentheses: +(-14x(-)/(-147x^2+21x), so:

-14x(-)/(-147x^2+21x

We add all the numbers together, and all the variables

-14x0/(-147x^2+21x

We multiply all the terms by the denominator


-14x0

We add all the numbers together, and all the variables

-14x

Back to the equation:

+(-14x)



We get rid of parentheses

(-18x)/(-147x^2+21x)-14x=0

We multiply all the terms by the denominator


-14x*(-147x^2+21x)+(-18x)=0

We multiply parentheses

2058x^3-294x^2+(-18x)=0

We get rid of parentheses

2058x^3-294x^2-18x=0

We do not support expression: x^3

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