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-6/5y+6=-3/2y=7/5
We move all terms to the left:
-6/5y+6-(-3/2y)=0
Domain of the equation: 5y!=0
y!=0/5
y!=0
y∈R
Domain of the equation: 2y)!=0We get rid of parentheses
y!=0/1
y!=0
y∈R
-6/5y+3/2y+6=0
We calculate fractions
(-12y)/10y^2+15y/10y^2+6=0
We multiply all the terms by the denominator
(-12y)+15y+6*10y^2=0
We add all the numbers together, and all the variables
15y+(-12y)+6*10y^2=0
Wy multiply elements
60y^2+15y+(-12y)=0
We get rid of parentheses
60y^2+15y-12y=0
We add all the numbers together, and all the variables
60y^2+3y=0
a = 60; b = 3; c = 0;
Δ = b2-4ac
Δ = 32-4·60·0
Δ = 9
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{9}=3$$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(3)-3}{2*60}=\frac{-6}{120} =-1/20 $$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(3)+3}{2*60}=\frac{0}{120} =0 $
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