-6,b=(5/2)

Solution for -6,b=(5/2) equation:

-6.b=(5/2)

We move all terms to the left:

-6.b-((5/2))=0

We add all the numbers together, and all the variables

-6.b-((+5/2))=0

We add all the numbers together, and all the variables

-6b-((+5/2))=0

We multiply all the terms by the denominator


-6b*2))-((+5=0

Wy multiply elements

-12b^2+5=0

a = -12; b = 0; c = +5;
Δ = b2-4ac
Δ = 02-4·(-12)·5
Δ = 240
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$b_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$b_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{240}=\sqrt{16*15}=\sqrt{16}*\sqrt{15}=4\sqrt{15}$
$b_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-4\sqrt{15}}{2*-12}=\frac{0-4\sqrt{15}}{-24}
=-\frac{4\sqrt{15}}{-24}
=-\frac{\sqrt{15}}{-6}
$
$b_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+4\sqrt{15}}{2*-12}=\frac{0+4\sqrt{15}}{-24}
=\frac{4\sqrt{15}}{-24}
=\frac{\sqrt{15}}{-6}
$