-6+18n2+19n=20

Solution for -6+18n2+19n=20 equation:

-6+18n^2+19n=20

We move all terms to the left:

-6+18n^2+19n-(20)=0

We add all the numbers together, and all the variables

18n^2+19n-26=0

a = 18; b = 19; c = -26;
Δ = b2-4ac
Δ = 192-4·18·(-26)
Δ = 2233
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$n_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$n_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$n_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(19)-\sqrt{2233}}{2*18}=\frac{-19-\sqrt{2233}}{36}
$
$n_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(19)+\sqrt{2233}}{2*18}=\frac{-19+\sqrt{2233}}{36}
$