-6(y-6)+6=3y-12

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Solution for -6(y-6)+6=3y-12 equation: 



-6(y-6)+6=3y-12

We move all terms to the left:

-6(y-6)+6-(3y-12)=0

We multiply parentheses

-6y-(3y-12)+36+6=0

We get rid of parentheses

-6y-3y+12+36+6=0

We add all the numbers together, and all the variables

-9y+54=0

We move all terms containing y to the left, all other terms to the right

-9y=-54

y=-54/-9

y=+6

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