-6(y+3)=-8y-20

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Solution for -6(y+3)=-8y-20 equation:



-6(y+3)=-8y-20
We move all terms to the left:
-6(y+3)-(-8y-20)=0
We multiply parentheses
-6y-(-8y-20)-18=0
We get rid of parentheses
-6y+8y+20-18=0
We add all the numbers together, and all the variables
2y+2=0
We move all terms containing y to the left, all other terms to the right
2y=-2
y=-2/2
y=-1

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