-6(y+1)=8y-8+2(2y+5)

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Solution for -6(y+1)=8y-8+2(2y+5) equation: 



-6(y+1)=8y-8+2(2y+5)

We move all terms to the left:

-6(y+1)-(8y-8+2(2y+5))=0

We multiply parentheses

-6y-(8y-8+2(2y+5))-6=0



We calculate terms in parentheses: -(8y-8+2(2y+5)), so:

8y-8+2(2y+5)

determiningTheFunctionDomain
8y+2(2y+5)-8

We multiply parentheses

8y+4y+10-8

We add all the numbers together, and all the variables

12y+2

Back to the equation:

-(12y+2)



We get rid of parentheses

-6y-12y-2-6=0

We add all the numbers together, and all the variables

-18y-8=0

We move all terms containing y to the left, all other terms to the right

-18y=8

y=8/-18

y=-4/9

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