-6(x-7)+8x=2(2x-9)-10

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Solution for -6(x-7)+8x=2(2x-9)-10 equation: 



-6(x-7)+8x=2(2x-9)-10

We move all terms to the left:

-6(x-7)+8x-(2(2x-9)-10)=0

We add all the numbers together, and all the variables

8x-6(x-7)-(2(2x-9)-10)=0

We multiply parentheses

8x-6x-(2(2x-9)-10)+42=0



We calculate terms in parentheses: -(2(2x-9)-10), so:

2(2x-9)-10

We multiply parentheses

4x-18-10

We add all the numbers together, and all the variables

4x-28

Back to the equation:

-(4x-28)



We add all the numbers together, and all the variables

2x-(4x-28)+42=0

We get rid of parentheses

2x-4x+28+42=0

We add all the numbers together, and all the variables

-2x+70=0

We move all terms containing x to the left, all other terms to the right

-2x=-70

x=-70/-2

x=+35

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