-6(x-2)+3x=3(x+3)+21

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Solution for -6(x-2)+3x=3(x+3)+21 equation: 



-6(x-2)+3x=3(x+3)+21

We move all terms to the left:

-6(x-2)+3x-(3(x+3)+21)=0

We add all the numbers together, and all the variables

3x-6(x-2)-(3(x+3)+21)=0

We multiply parentheses

3x-6x-(3(x+3)+21)+12=0



We calculate terms in parentheses: -(3(x+3)+21), so:

3(x+3)+21

We multiply parentheses

3x+9+21

We add all the numbers together, and all the variables

3x+30

Back to the equation:

-(3x+30)



We add all the numbers together, and all the variables

-3x-(3x+30)+12=0

We get rid of parentheses

-3x-3x-30+12=0

We add all the numbers together, and all the variables

-6x-18=0

We move all terms containing x to the left, all other terms to the right

-6x=18

x=18/-6

x=-3

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