-6(x-1)+x=2(3x+1)-8+x

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Solution for -6(x-1)+x=2(3x+1)-8+x equation: 



-6(x-1)+x=2(3x+1)-8+x

We move all terms to the left:

-6(x-1)+x-(2(3x+1)-8+x)=0

We add all the numbers together, and all the variables

x-6(x-1)-(2(3x+1)-8+x)=0

We multiply parentheses

x-6x-(2(3x+1)-8+x)+6=0



We calculate terms in parentheses: -(2(3x+1)-8+x), so:

2(3x+1)-8+x

determiningTheFunctionDomain
2(3x+1)+x-8

We add all the numbers together, and all the variables

x+2(3x+1)-8

We multiply parentheses

x+6x+2-8

We add all the numbers together, and all the variables

7x-6

Back to the equation:

-(7x-6)



We add all the numbers together, and all the variables

-5x-(7x-6)+6=0

We get rid of parentheses

-5x-7x+6+6=0

We add all the numbers together, and all the variables

-12x+12=0

We move all terms containing x to the left, all other terms to the right

-12x=-12

x=-12/-12

x=1

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