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-6(x+3)+4(3x-4)=5(x-6)+11
We move all terms to the left:
-6(x+3)+4(3x-4)-(5(x-6)+11)=0
We multiply parentheses
-6x+12x-(5(x-6)+11)-18-16=0
We calculate terms in parentheses: -(5(x-6)+11), so:We add all the numbers together, and all the variables
5(x-6)+11
We multiply parentheses
5x-30+11
We add all the numbers together, and all the variables
5x-19
Back to the equation:
-(5x-19)
6x-(5x-19)-34=0
We get rid of parentheses
6x-5x+19-34=0
We add all the numbers together, and all the variables
x-15=0
We move all terms containing x to the left, all other terms to the right
x=15
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