-6(v+2)=4v-2+2(4v+3)

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Solution for -6(v+2)=4v-2+2(4v+3) equation: 



-6(v+2)=4v-2+2(4v+3)

We move all terms to the left:

-6(v+2)-(4v-2+2(4v+3))=0

We multiply parentheses

-6v-(4v-2+2(4v+3))-12=0



We calculate terms in parentheses: -(4v-2+2(4v+3)), so:

4v-2+2(4v+3)

determiningTheFunctionDomain
4v+2(4v+3)-2

We multiply parentheses

4v+8v+6-2

We add all the numbers together, and all the variables

12v+4

Back to the equation:

-(12v+4)



We get rid of parentheses

-6v-12v-4-12=0

We add all the numbers together, and all the variables

-18v-16=0

We move all terms containing v to the left, all other terms to the right

-18v=16

v=16/-18

v=-8/9

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