-6(v+2)=2(1-3v)-8

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Solution for -6(v+2)=2(1-3v)-8 equation:



-6(v+2)=2(1-3v)-8
We move all terms to the left:
-6(v+2)-(2(1-3v)-8)=0
We add all the numbers together, and all the variables
-6(v+2)-(2(-3v+1)-8)=0
We multiply parentheses
-6v-(2(-3v+1)-8)-12=0
We calculate terms in parentheses: -(2(-3v+1)-8), so:
2(-3v+1)-8
We multiply parentheses
-6v+2-8
We add all the numbers together, and all the variables
-6v-6
Back to the equation:
-(-6v-6)
We get rid of parentheses
-6v+6v+6-12=0
We add all the numbers together, and all the variables
-6!=0
There is no solution for this equation

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