-6(u+1)=4u-6+2(4u+3)

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Solution for -6(u+1)=4u-6+2(4u+3) equation: 



-6(u+1)=4u-6+2(4u+3)

We move all terms to the left:

-6(u+1)-(4u-6+2(4u+3))=0

We multiply parentheses

-6u-(4u-6+2(4u+3))-6=0



We calculate terms in parentheses: -(4u-6+2(4u+3)), so:

4u-6+2(4u+3)

determiningTheFunctionDomain
4u+2(4u+3)-6

We multiply parentheses

4u+8u+6-6

We add all the numbers together, and all the variables

12u

Back to the equation:

-(12u)



We add all the numbers together, and all the variables

-18u-6=0

We move all terms containing u to the left, all other terms to the right

-18u=6

u=6/-18

u=-1/3

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