-6(u+1)+4(u-1)=3(u+2)

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Solution for -6(u+1)+4(u-1)=3(u+2) equation: 



-6(u+1)+4(u-1)=3(u+2)

We move all terms to the left:

-6(u+1)+4(u-1)-(3(u+2))=0

We multiply parentheses

-6u+4u-(3(u+2))-6-4=0



We calculate terms in parentheses: -(3(u+2)), so:

3(u+2)

We multiply parentheses

3u+6

Back to the equation:

-(3u+6)



We add all the numbers together, and all the variables

-2u-(3u+6)-10=0

We get rid of parentheses

-2u-3u-6-10=0

We add all the numbers together, and all the variables

-5u-16=0

We move all terms containing u to the left, all other terms to the right

-5u=16

u=16/-5

u=-3+1/5

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