-6(n+3)+22=-3n-2

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Solution for -6(n+3)+22=-3n-2 equation: 



-6(n+3)+22=-3n-2

We move all terms to the left:

-6(n+3)+22-(-3n-2)=0

We multiply parentheses

-6n-(-3n-2)-18+22=0

We get rid of parentheses

-6n+3n+2-18+22=0

We add all the numbers together, and all the variables

-3n+6=0

We move all terms containing n to the left, all other terms to the right

-3n=-6

n=-6/-3

n=+2

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