-6(k+1)-k-11=-7(k+3)+4

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Solution for -6(k+1)-k-11=-7(k+3)+4 equation: 



-6(k+1)-k-11=-7(k+3)+4

We move all terms to the left:

-6(k+1)-k-11-(-7(k+3)+4)=0

We add all the numbers together, and all the variables

-1k-6(k+1)-(-7(k+3)+4)-11=0

We multiply parentheses

-1k-6k-(-7(k+3)+4)-6-11=0



We calculate terms in parentheses: -(-7(k+3)+4), so:

-7(k+3)+4

We multiply parentheses

-7k-21+4

We add all the numbers together, and all the variables

-7k-17

Back to the equation:

-(-7k-17)



We add all the numbers together, and all the variables

-7k-(-7k-17)-17=0

We get rid of parentheses

-7k+7k+17-17=0

We add all the numbers together, and all the variables

=0

k=0/1

k=0

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