-6(b+3)=+6b(-4b+3)

Solution for -6(b+3)=+6b(-4b+3) equation:

-6(b+3)=+6b(-4b+3)

We move all terms to the left:

-6(b+3)-(+6b(-4b+3))=0

We multiply parentheses

-6b-(+6b(-4b+3))-18=0


We calculate terms in parentheses: -(+6b(-4b+3)), so:

+6b(-4b+3)

determiningTheFunctionDomain
6b(-4b+3)

We multiply parentheses

-24b^2+18b

Back to the equation:

-(-24b^2+18b)


We get rid of parentheses

24b^2-18b-6b-18=0

We add all the numbers together, and all the variables

24b^2-24b-18=0

a = 24; b = -24; c = -18;
Δ = b2-4ac
Δ = -242-4·24·(-18)
Δ = 2304
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$b_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$b_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{2304}=48$
$b_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-24)-48}{2*24}=\frac{-24}{48}
=-1/2
$
$b_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-24)+48}{2*24}=\frac{72}{48}
=1+1/2
$