-6(6x+10)=-3x(12x+20)

Solution for -6(6x+10)=-3x(12x+20) equation:

-6(6x+10)=-3x(12x+20)

We move all terms to the left:

-6(6x+10)-(-3x(12x+20))=0

We multiply parentheses

-36x-(-3x(12x+20))-60=0


We calculate terms in parentheses: -(-3x(12x+20)), so:

-3x(12x+20)

We multiply parentheses

-36x^2-60x

Back to the equation:

-(-36x^2-60x)


We get rid of parentheses

36x^2+60x-36x-60=0

We add all the numbers together, and all the variables

36x^2+24x-60=0

a = 36; b = 24; c = -60;
Δ = b2-4ac
Δ = 242-4·36·(-60)
Δ = 9216
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{9216}=96$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(24)-96}{2*36}=\frac{-120}{72}
=-1+2/3
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(24)+96}{2*36}=\frac{72}{72}
=1
$