-6(4z+2)=-6(4z)

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Solution for -6(4z+2)=-6(4z) equation: 



-6(4z+2)=-6(4z)

We move all terms to the left:

-6(4z+2)-(-6(4z))=0

We multiply parentheses

-24z-(-64z)-12=0

We get rid of parentheses

-24z+64z-12=0

We add all the numbers together, and all the variables

40z-12=0

We move all terms containing z to the left, all other terms to the right

40z=12

z=12/40

z=3/10

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