-6(3y-4)+5y=3(y+4)

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Solution for -6(3y-4)+5y=3(y+4) equation: 



-6(3y-4)+5y=3(y+4)

We move all terms to the left:

-6(3y-4)+5y-(3(y+4))=0

We add all the numbers together, and all the variables

5y-6(3y-4)-(3(y+4))=0

We multiply parentheses

5y-18y-(3(y+4))+24=0



We calculate terms in parentheses: -(3(y+4)), so:

3(y+4)

We multiply parentheses

3y+12

Back to the equation:

-(3y+12)



We add all the numbers together, and all the variables

-13y-(3y+12)+24=0

We get rid of parentheses

-13y-3y-12+24=0

We add all the numbers together, and all the variables

-16y+12=0

We move all terms containing y to the left, all other terms to the right

-16y=-12

y=-12/-16

y=3/4

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